Solid State Physics 2014
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Re: Diatomic Chain at BZ Boundaries

Posted by K on April 17, 2014, 4:38 pm, in reply to "Re: Diatomic Chain at BZ Boundaries"

 Hmm, the general equation I reached is: ( m1*w^2-2K . . . . K(1+exp(ika)) ) (Ax) = (0) ( K(1+exp(-ika)). . . . m2*w^2-2K ) (Ay) = (0) That's meant to be a matrix equation with vectors, tried to put dots between terms to line things up right, but not sure how clear it'll come out. And w is omega and K is kappa. So what I have is like an eigenvalue equation, but I didn't put the omega onto the other side. I found the values of omega at the BZ boundary to be square root(2K/m1) and square root(2K/m2). Putting k=pi/a and omega = square root (2K/m1) makes all terms in the matrix 0. And putting k=pi/a and omega = square root (2K/m2) gives non-zero diagonal terms but zero off-diagonals. Which I guess can't be right... Not sure if the matrix is wrong, if the values of omega at the boundary are wrong, or if I'm making a mistake after that. The matrix seems to work for the k=0 case...
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 Message Thread Diatomic Chain at BZ Boundaries - K April 17, 2014, 1:38 pm Re: Diatomic Chain at BZ Boundaries - Steve Simon April 17, 2014, 3:51 pm Re: Diatomic Chain at BZ Boundaries - K April 17, 2014, 4:38 pm Re: Diatomic Chain at BZ Boundaries - Steve Simon April 17, 2014, 5:16 pm Re: Diatomic Chain at BZ Boundaries - K April 17, 2014, 5:25 pm Re: Diatomic Chain at BZ Boundaries - Steve Simon April 17, 2014, 5:26 pm Re: Diatomic Chain at BZ Boundaries - K April 17, 2014, 5:38 pm Re: Diatomic Chain at BZ Boundaries - Steve Simon April 17, 2014, 5:38 pm « Back to index