Solid State Physics 2013
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Q2.4

Posted by Lost :/ on February 3, 2013, 8:29 pm

 The text introduction to question 2.4 gives an expression for Exp[-B*V(x)], and then guides me to use +- infinity as limits of integration. By making the substitution r=(x-x0) the relevant integrals become much simpler, although this (or an incorrect application of this) may be my problem :/ Setting denominator D=Int[Exp[-BV(x)]]dx and expanding the Exp[-B*V(x)] as given in the question gives two integrals where I get the first to be equal to ((2*pi)/(Bk))^(1/2) and the second to be equal to 0, however it is the second integral which is multiplied by BK_3/6 The next part of the question (or the same part?) gives d_B/dT = (k_b*K_3)/2k^2 which presumably implies that _B = k_3/2K^2 B + some term constant with respect to T. If anyone could kindly explain where I've messed this up (since my expression gives the numerator to be 0) I would very much appreciate it Thanks!

 Message Thread Q2.4 - Lost :/ February 3, 2013, 8:29 pm Re: Q2.4 - Steve Simon February 3, 2013, 9:09 pm Re: Q2.4 - Found February 3, 2013, 10:04 pm « Back to index