Re: Q 2.6a
Posted by Steve Simon on February 3, 2013, 12:34 pm, in reply to "Re: Q 2.6a"
[p1,x1] = [p2,x2]= - i hbar
but [p1,x2] = [p2,x1]=0
prel=(p1-p2)/2
xrel=(x1 - x2)
gives
[prel,xrel]= -i hbar
No?
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Message Thread
- Q 2.6a - student February 2, 2013, 5:13 pm
- Re: Q 2.6a - really? February 3, 2013, 12:04 pm
- Re: Q 2.6a - is it wrong? February 3, 2013, 12:16 pm
- Re: Q 2.6a - Steve Simon February 3, 2013, 12:34 pm
- Re: Q 2.6a - Steve Simon February 3, 2013, 11:15 am
- Re: Q 2.6a - Steve Simon February 2, 2013, 5:18 pm
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